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Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
这是一道比较简单的题目,但也是面试中容易考到的题目,主要考察我们对于整数越界时的处理,我们要根据题目的要求进行不同的处理。这个题目要求我们返回一个int型的整数,因此我们对于越界的数统一返回一个合理的整数。代码如下:
其中对于result > (Integer.MAX_VALUE - abs % 10) / 10的判断就是对越界整数的处理,这里我们统一返回0。
Example1: x = 123, return 321
Example2: x = -123, return -321
这是一道比较简单的题目,但也是面试中容易考到的题目,主要考察我们对于整数越界时的处理,我们要根据题目的要求进行不同的处理。这个题目要求我们返回一个int型的整数,因此我们对于越界的数统一返回一个合理的整数。代码如下:
public class Solution { public int reverse(int x) { int result = 0; int abs = Math.abs(x); while(abs != 0) { if(result > (Integer.MAX_VALUE - abs % 10) / 10) return 0; result = result * 10 + abs % 10; abs /= 10; } return x < 0 ? -result : result; } }
其中对于result > (Integer.MAX_VALUE - abs % 10) / 10的判断就是对越界整数的处理,这里我们统一返回0。
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