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Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
这道题目实际上就是让我们实现java中的indexOf方法,有关字符串匹配的问题,有一个时间复杂为线性时间的算法-KMP,这里我们使用java中的substring方法来解决。代码如下:
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
这道题目实际上就是让我们实现java中的indexOf方法,有关字符串匹配的问题,有一个时间复杂为线性时间的算法-KMP,这里我们使用java中的substring方法来解决。代码如下:
public class Solution { public int strStr(String haystack, String needle) { if(haystack == null || needle == null ) return 0; int m = haystack.length(); int n = needle.length(); for(int i = 0; i <= m - n; i++) { String s = haystack.substring(i, i + n); if(s.equals(needle)) return i; } return -1; } }
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